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2x^2-27x+12=0
a = 2; b = -27; c = +12;
Δ = b2-4ac
Δ = -272-4·2·12
Δ = 633
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{633}}{2*2}=\frac{27-\sqrt{633}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{633}}{2*2}=\frac{27+\sqrt{633}}{4} $
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