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2x^2-30x+52=0
a = 2; b = -30; c = +52;
Δ = b2-4ac
Δ = -302-4·2·52
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-22}{2*2}=\frac{8}{4} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+22}{2*2}=\frac{52}{4} =13 $
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