If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2-3x=-1
We move all terms to the left:
2x^2-3x-(-1)=0
We add all the numbers together, and all the variables
2x^2-3x+1=0
a = 2; b = -3; c = +1;
Δ = b2-4ac
Δ = -32-4·2·1
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-1}{2*2}=\frac{2}{4} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+1}{2*2}=\frac{4}{4} =1 $
| 3y^2-20y-63=0 | | 2-9y=7 | | 125m-100m+42,975=45,000-200m | | (X+6)+y=-2 | | 2(x-1)(x-2)=(x-5)(x+4)+5x | | 70=5(3x-2)+5x | | 15x+3=108 | | 9/5+3/5x=89/30 | | 1/4=2m | | -3.5-3.5x=1.5x+14 | | 0.5r-3=12-4.5r | | 7(n-1)=-3(3+n) | | (3x^2+1)(x^2-4)=0 | | 4(a-)+4=2a-6 | | 98=(2x) | | 2(c+6)=5+3(c-1) | | X^2-5x+4=x^2+6x-11 | | 1/2h*1/3(h-6)=5/6h*2 | | 9x2-8x-1=0 | | 5x+6-11=4x-2 | | (x-18)^2-(12)=0 | | 9×x=18 | | 4x^2-((2x+9)((9x-4))-36=0 | | (x-18)^2=12 | | 9/x=25 | | 32=10+b+15 | | 35x^2-18x-60=0 | | 1x+55=5x | | 1/x+3=1/2x-3 | | x-0.18x=505.94 | | 3x2+4-8x=0 | | 8((3)/(4)x+2)=8((3)/(8)x-4) |