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2x^2-3x=x2-5x-1
We move all terms to the left:
2x^2-3x-(x2-5x-1)=0
We add all the numbers together, and all the variables
2x^2-(+x^2-5x-1)-3x=0
We get rid of parentheses
2x^2-x^2+5x-3x+1=0
We add all the numbers together, and all the variables
x^2+2x+1=0
a = 1; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-2}{2}=-1$
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