2x2-46x+252=0

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Solution for 2x2-46x+252=0 equation:



2x^2-46x+252=0
a = 2; b = -46; c = +252;
Δ = b2-4ac
Δ = -462-4·2·252
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-10}{2*2}=\frac{36}{4} =9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+10}{2*2}=\frac{56}{4} =14 $

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