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2x^2-4x-3x+6=0
We add all the numbers together, and all the variables
2x^2-7x+6=0
a = 2; b = -7; c = +6;
Δ = b2-4ac
Δ = -72-4·2·6
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-1}{2*2}=\frac{6}{4} =1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+1}{2*2}=\frac{8}{4} =2 $
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