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2x^2-57x+391=0
a = 2; b = -57; c = +391;
Δ = b2-4ac
Δ = -572-4·2·391
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-11}{2*2}=\frac{46}{4} =11+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+11}{2*2}=\frac{68}{4} =17 $
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