2x2-5=3x2-12x+31

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Solution for 2x2-5=3x2-12x+31 equation: 



2x^2-5=3x^2-12x+31

We move all terms to the left:

2x^2-5-(3x^2-12x+31)=0

We get rid of parentheses

2x^2-3x^2+12x-31-5=0

We add all the numbers together, and all the variables

-1x^2+12x-36=0

a = -1; b = 12; c = -36;
Δ = b2-4ac
Δ = 122-4·(-1)·(-36)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-12}{-2}=+6$

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