If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2-5x-13=0
a = 2; b = -5; c = -13;
Δ = b2-4ac
Δ = -52-4·2·(-13)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{129}}{2*2}=\frac{5-\sqrt{129}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{129}}{2*2}=\frac{5+\sqrt{129}}{4} $
| 0.4x+x=-2.56 | | 31=5(v+2)-8v | | 3(x+4)-3=2(2x+5)-x | | 6a-18=5a | | 2x6x=1,000 | | 6x-11-5x+25=-6 | | (3x+1)/50=1/5 | | 6x+4=8x-11 | | -1/4x-7=11 | | (x+1/x2+5x-14)x=0 | | 9(k+9)-(8k+3)=-2 | | -9(t—2)=4(t—15) | | |3y+1|=10 | | 7x+3-2×+7=180 | | -9(t–2)=4(t–15) | | 11a-11=15+9a | | -3r+10=15r–8 | | X/8+x/2=-2 | | 55-23y=14 | | -3r+10=15r—8 | | 4/3x+2/3x=1/3+5 | | 0.5x+0.25=0.33x+1.25 | | x3-11=29 | | 3(x+9)^2-12=63 | | 4u+16=68 | | -4=5x=2(3x-4) | | 21=x/3+12 | | 7x-12=8x=29-x | | −x+4(1+5x)=156 | | 25-x=15-(x+10) | | 3b=b-18 | | 3a+2=×-6 |