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2x^2-5x=x2-3x+24
We move all terms to the left:
2x^2-5x-(x2-3x+24)=0
We add all the numbers together, and all the variables
2x^2-(+x^2-3x+24)-5x=0
We get rid of parentheses
2x^2-x^2+3x-5x-24=0
We add all the numbers together, and all the variables
x^2-2x-24=0
a = 1; b = -2; c = -24;
Δ = b2-4ac
Δ = -22-4·1·(-24)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10}{2*1}=\frac{-8}{2} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10}{2*1}=\frac{12}{2} =6 $
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