2x2-x+1/8=0

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Solution for 2x2-x+1/8=0 equation: 



2x^2-x+1/8=0

We add all the numbers together, and all the variables

2x^2-1x+1/8=0

We multiply all the terms by the denominator


2x^2*8-1x*8+1=0

Wy multiply elements

16x^2-8x+1=0

a = 16; b = -8; c = +1;
Δ = b2-4ac
Δ = -82-4·16·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{8}{32}=1/4$

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