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2x^2-x=100
We move all terms to the left:
2x^2-x-(100)=0
We add all the numbers together, and all the variables
2x^2-1x-100=0
a = 2; b = -1; c = -100;
Δ = b2-4ac
Δ = -12-4·2·(-100)
Δ = 801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{801}=\sqrt{9*89}=\sqrt{9}*\sqrt{89}=3\sqrt{89}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-3\sqrt{89}}{2*2}=\frac{1-3\sqrt{89}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+3\sqrt{89}}{2*2}=\frac{1+3\sqrt{89}}{4} $
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