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2x^2-x=210
We move all terms to the left:
2x^2-x-(210)=0
We add all the numbers together, and all the variables
2x^2-1x-210=0
a = 2; b = -1; c = -210;
Δ = b2-4ac
Δ = -12-4·2·(-210)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-41}{2*2}=\frac{-40}{4} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+41}{2*2}=\frac{42}{4} =10+1/2 $
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