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2x^2-x=2x-1
We move all terms to the left:
2x^2-x-(2x-1)=0
We add all the numbers together, and all the variables
2x^2-1x-(2x-1)=0
We get rid of parentheses
2x^2-1x-2x+1=0
We add all the numbers together, and all the variables
2x^2-3x+1=0
a = 2; b = -3; c = +1;
Δ = b2-4ac
Δ = -32-4·2·1
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-1}{2*2}=\frac{2}{4} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+1}{2*2}=\frac{4}{4} =1 $
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