2x2=-8+8x

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Solution for 2x2=-8+8x equation: 



2x^2=-8+8x

We move all terms to the left:

2x^2-(-8+8x)=0

We add all the numbers together, and all the variables

2x^2-(8x-8)=0

We get rid of parentheses

2x^2-8x+8=0

a = 2; b = -8; c = +8;
Δ = b2-4ac
Δ = -82-4·2·8
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{8}{4}=2$

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