2x5/2+5x3/2=7x1/2

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Solution for 2x5/2+5x3/2=7x1/2 equation:


x in (-oo:+oo)

(2*x^5)/2+(5*x^3)/2 = (7*x^1)/2 // - (7*x^1)/2

(2*x^5)/2+(5*x^3)/2-((7*x^1)/2) = 0

(2*x^5)/2+(5*x^3)/2+(-7/2)*x = 0

x^5+5/2*x^3-7/2*x = 0

x*(x^4+5/2*x^2-7/2) = 0

x^4+(5/2)*x^2-7/2 = 0

x^4+(5/2)*x^2-7/2 = 0 // * 0

{ 1, -1, 7, -7 }

1

x = 1

2*x^4+5*x^2-7 = 0

1

x-1

2*x^3+2*x^2+7*x+7

2*x^4+5*x^2-7

x-1

2*x^3-2*x^4

2*x^3+5*x^2-7

2*x^2-2*x^3

7*x^2-7

7*x-7*x^2

7*x-7

7-7*x

0

2*x^3+2*x^2+7*x+7 = 0

{ 1, -1, 7, -7 }

1

x = 1

2*x^3+2*x^2+7*x+7 = 18

1

-1

x = -1

2*x^3+2*x^2+7*x+7 = 0

-1

x+1

2*x^2+7

2*x^3+2*x^2+7*x+7

x+1

-2*x^3-2*x^2

7*x+7

-7*x-7

0

2*x^2+7 = 0

DELTA = 0^2-(2*4*7)

DELTA = -56

DELTA < 0

x in { 1, -1}

x = 0

x = 0

x in { 1, -1, 0 }

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