2x=(21x/15)+6

Solution for 2x=(21x/15)+6 equation:

2x=(21x/15)+6

We move all terms to the left:

2x-((21x/15)+6)=0

We add all the numbers together, and all the variables

2x-((+21x/15)+6)=0

We multiply all the terms by the denominator


2x*15)+6)-((+21x=0

We add all the numbers together, and all the variables

21x+2x*15)+6)-((=0

Wy multiply elements

30x^2+21x=0

a = 30; b = 21; c = 0;
Δ = b2-4ac
Δ = 212-4·30·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-21}{2*30}=\frac{-42}{60}
=-7/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+21}{2*30}=\frac{0}{60}
=0
$