2x=(320/28

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Solution for 2x=(320/28 equation: 



2x=(320/28

We move all terms to the left:

2x-((320/28)=0

We add all the numbers together, and all the variables

2x-((+320/28)=0

We multiply all the terms by the denominator


2x*28)-((+320=0

Wy multiply elements

56x^2=0

a = 56; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·56·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{112}=0$

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