2x=(3x-12)+(4+9)

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Solution for 2x=(3x-12)+(4+9) equation:



2x=(3x-12)+(4+9)
We move all terms to the left:
2x-((3x-12)+(4+9))=0
We add all the numbers together, and all the variables
2x-((3x-12)+13)=0
We calculate terms in parentheses: -((3x-12)+13), so:
(3x-12)+13
We get rid of parentheses
3x-12+13
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
We get rid of parentheses
2x-3x-1=0
We add all the numbers together, and all the variables
-1x-1=0
We move all terms containing x to the left, all other terms to the right
-x=1
x=1/-1
x=-1

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