2x=(4/3)x+20

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Solution for 2x=(4/3)x+20 equation: 



2x=(4/3)x+20

We move all terms to the left:

2x-((4/3)x+20)=0



Domain of the equation: 3)x+20)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

2x-((+4/3)x+20)=0

We multiply all the terms by the denominator


2x*3)x+20)-((+4=0

Wy multiply elements

6x^2+4=0

a = 6; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·6·4
Δ = -96
Delta is less than zero, so there is no solution for the equation

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