2x=-40-3(3x+5)

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Solution for 2x=-40-3(3x+5) equation: 



2x=-40-3(3x+5)

We move all terms to the left:

2x-(-40-3(3x+5))=0



We calculate terms in parentheses: -(-40-3(3x+5)), so:

-40-3(3x+5)

determiningTheFunctionDomain
-3(3x+5)-40

We multiply parentheses

-9x-15-40

We add all the numbers together, and all the variables

-9x-55

Back to the equation:

-(-9x-55)



We get rid of parentheses

2x+9x+55=0

We add all the numbers together, and all the variables

11x+55=0

We move all terms containing x to the left, all other terms to the right

11x=-55

x=-55/11

x=-5

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