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2x=10(1/5x)
We move all terms to the left:
2x-(10(1/5x))=0
Domain of the equation: 5x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x-(10(+1/5x))=0
We multiply all the terms by the denominator
2x*5x))-(10(+1=0
Wy multiply elements
10x^2+1=0
a = 10; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·10·1
Δ = -40
Delta is less than zero, so there is no solution for the equation
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