2x=12(4x2)

Solution for 2x=12(4x2) equation:

2x=12(4x^2)

We move all terms to the left:

2x-(12(4x^2))=0

determiningTheFunctionDomain
2x-124x^2=0

We add all the numbers together, and all the variables

-124x^2+2x=0

a = -124; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-124)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-124}=\frac{-4}{-248}
=1/62
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-124}=\frac{0}{-248}
=0
$