2x=3(x+1)+4(x-2)=0

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Solution for 2x=3(x+1)+4(x-2)=0 equation: 



2x=3(x+1)+4(x-2)=0

We move all terms to the left:

2x-(3(x+1)+4(x-2))=0



We calculate terms in parentheses: -(3(x+1)+4(x-2)), so:

3(x+1)+4(x-2)

We multiply parentheses

3x+4x+3-8

We add all the numbers together, and all the variables

7x-5

Back to the equation:

-(7x-5)



We get rid of parentheses

2x-7x+5=0

We add all the numbers together, and all the variables

-5x+5=0

We move all terms containing x to the left, all other terms to the right

-5x=-5

x=-5/-5

x=1

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