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2x=3/2x+30
We move all terms to the left:
2x-(3/2x+30)=0
Domain of the equation: 2x+30)!=0We get rid of parentheses
x∈R
2x-3/2x-30=0
We multiply all the terms by the denominator
2x*2x-30*2x-3=0
Wy multiply elements
4x^2-60x-3=0
a = 4; b = -60; c = -3;
Δ = b2-4ac
Δ = -602-4·4·(-3)
Δ = 3648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3648}=\sqrt{64*57}=\sqrt{64}*\sqrt{57}=8\sqrt{57}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-8\sqrt{57}}{2*4}=\frac{60-8\sqrt{57}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+8\sqrt{57}}{2*4}=\frac{60+8\sqrt{57}}{8} $
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