2x=3/x-4+x+5/x-4

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Solution for 2x=3/x-4+x+5/x-4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x = x+3/x+5/x-4-4 // - x+3/x+5/x-4-4

2*x-x-(3/x)-(5/x)+4+4 = 0

2*x-x-3*x^-1-5*x^-1+4+4 = 0

1*x^1-8*x^-1+8*x^0 = 0

(1*x^2+8*x^1-8*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2+8*x^1-8*x^0) = 0

x^1

x^2+8*x-8 = 0

x^2+8*x-8 = 0

DELTA = 8^2-(-8*1*4)

DELTA = 96

DELTA > 0

x = (96^(1/2)-8)/(1*2) or x = (-96^(1/2)-8)/(1*2)

x = (4*6^(1/2)-8)/2 or x = (-4*6^(1/2)-8)/2

x in { (-4*6^(1/2)-8)/2, (4*6^(1/2)-8)/2} 

x in { (-4*6^(1/2)-8)/2, (4*6^(1/2)-8)/2 }

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