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2x=3x*3x-5
We move all terms to the left:
2x-(3x*3x-5)=0
We get rid of parentheses
2x-3x*3x+5=0
Wy multiply elements
-9x^2+2x+5=0
a = -9; b = 2; c = +5;
Δ = b2-4ac
Δ = 22-4·(-9)·5
Δ = 184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{184}=\sqrt{4*46}=\sqrt{4}*\sqrt{46}=2\sqrt{46}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{46}}{2*-9}=\frac{-2-2\sqrt{46}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{46}}{2*-9}=\frac{-2+2\sqrt{46}}{-18} $
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