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2x=400/x
We move all terms to the left:
2x-(400/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x-(+400/x)=0
We get rid of parentheses
2x-400/x=0
We multiply all the terms by the denominator
2x*x-400=0
Wy multiply elements
2x^2-400=0
a = 2; b = 0; c = -400;
Δ = b2-4ac
Δ = 02-4·2·(-400)
Δ = 3200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3200}=\sqrt{1600*2}=\sqrt{1600}*\sqrt{2}=40\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{2}}{2*2}=\frac{0-40\sqrt{2}}{4} =-\frac{40\sqrt{2}}{4} =-10\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{2}}{2*2}=\frac{0+40\sqrt{2}}{4} =\frac{40\sqrt{2}}{4} =10\sqrt{2} $
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