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2x=5-(9x/18)
We move all terms to the left:
2x-(5-(9x/18))=0
We add all the numbers together, and all the variables
2x-(5-(+9x/18))=0
We multiply all the terms by the denominator
2x*18))-(5-(+9x=0
We add all the numbers together, and all the variables
9x+2x*18))-(5-(=0
Wy multiply elements
36x^2+9x=0
a = 36; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·36·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*36}=\frac{-18}{72} =-1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*36}=\frac{0}{72} =0 $
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