2x=5x2-(7-8

Solution for 2x=5x2-(7-8 equation:

2x=5x^2-(7-8

We move all terms to the left:

2x-(5x^2-(7-8)=0

We add all the numbers together, and all the variables

2x-(5x^2-(-1)=0


We calculate terms in parentheses: -(5x^2-(-1), so:

5x^2-(-1

We add all the numbers together, and all the variables

5x^2

Back to the equation:

-(5x^2)


determiningTheFunctionDomain
-5x^2+2x=0

a = -5; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-5)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-5}=\frac{-4}{-10}
=2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-5}=\frac{0}{-10}
=0
$