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2x=9(x+2)/5
We move all terms to the left:
2x-(9(x+2)/5)=0
We multiply all the terms by the denominator
2x*5)-(9(x+2)=0
Wy multiply elements
10x^2=0
a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{20}=0$
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