2xsqaured-5x=7

Simple and best practice solution for 2xsqaured-5x=7 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 2xsqaured-5x=7 equation:


Simplifying
2xsqaured + -5x = 7

Solving
2adeqrsux + -5x = 7

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '5x' to each side of the equation.
2adeqrsux + -5x + 5x = 7 + 5x

Combine like terms: -5x + 5x = 0
2adeqrsux + 0 = 7 + 5x
2adeqrsux = 7 + 5x

Divide each side by '2deqrsux'.
a = 3.5d-1e-1q-1r-1s-1u-1x-1 + 2.5d-1e-1q-1r-1s-1u-1

Simplifying
a = 3.5d-1e-1q-1r-1s-1u-1x-1 + 2.5d-1e-1q-1r-1s-1u-1

Reorder the terms:
a = 2.5d-1e-1q-1r-1s-1u-1 + 3.5d-1e-1q-1r-1s-1u-1x-1

See similar equations:

| 11y-8y=18 | | m^1=6 | | 12x^2(x+3)+12(x-3)=3(x^2-9) | | ln(x)=ln(0.8)-0.23809 | | 2x+1=z+3 | | (7x+4)(8x^2+7x+6)= | | 2b+2b+2b+b+b=180 | | Since=-3cosx | | 2b+2b+2b+b+b= | | (x-2)(x+3)(2x-7)=0 | | 4y=16x-12 | | 2x/4x=0 | | 2cos^3(x)+cos^2(x)-5cos(x)+2=0 | | (5x-1)=(2x+5) | | x^2+y^2-4x+2y=0 | | 8+5-x=10 | | 24-6x+40=34 | | (Y-7)(y+9)=0 | | (4x+7)=(x+10) | | x^2+y^2=7z^2 | | (6+3x)=(x+14) | | -61=7y-.26 | | 52=(2x+20) | | (-9-6x)=(x-30) | | 5x+4+40=100 | | 5x+410=100 | | (x-4)+(x-9)=17 | | 0-20=20 | | 4x+12=10x-3 | | 47533.32=2(3.14r^2)+2*3.14*r*232 | | (x-2)-(3x-3)= | | 16616.88=2(3.14r^2)+2*3.14*r*105 |

Equations solver categories