2y(x-y)+y(3y-2x)=

Solution for 2y(x-y)+y(3y-2x)= equation:

Simplifying
2y(x + -1y) + y(3y + -2x) = 0
(x * 2y + -1y * 2y) + y(3y + -2x) = 0
(2xy + -2y2) + y(3y + -2x) = 0

Reorder the terms:
2xy + -2y2 + y(-2x + 3y) = 0
2xy + -2y2 + (-2x * y + 3y * y) = 0
2xy + -2y2 + (-2xy + 3y2) = 0

Reorder the terms:
2xy + -2xy + -2y2 + 3y2 = 0

Combine like terms: 2xy + -2xy = 0
0 + -2y2 + 3y2 = 0
-2y2 + 3y2 = 0

Combine like terms: -2y2 + 3y2 = 1y2
1y2 = 0

Solving
1y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '1'.
y2 = 0

Simplifying
y2 = 0

Take the square root of each side:
y = {0}