2y(y+3)=-17

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Solution for 2y(y+3)=-17 equation: 



2y(y+3)=-17

We move all terms to the left:

2y(y+3)-(-17)=0

We add all the numbers together, and all the variables

2y(y+3)+17=0

We multiply parentheses

2y^2+6y+17=0

a = 2; b = 6; c = +17;
Δ = b2-4ac
Δ = 62-4·2·17
Δ = -100
Delta is less than zero, so there is no solution for the equation

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