2y+(5y-3)=10y-(3y+2)

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Solution for 2y+(5y-3)=10y-(3y+2) equation:


Simplifying
2y + (5y + -3) = 10y + -1(3y + 2)

Reorder the terms:
2y + (-3 + 5y) = 10y + -1(3y + 2)

Remove parenthesis around (-3 + 5y)
2y + -3 + 5y = 10y + -1(3y + 2)

Reorder the terms:
-3 + 2y + 5y = 10y + -1(3y + 2)

Combine like terms: 2y + 5y = 7y
-3 + 7y = 10y + -1(3y + 2)

Reorder the terms:
-3 + 7y = 10y + -1(2 + 3y)
-3 + 7y = 10y + (2 * -1 + 3y * -1)
-3 + 7y = 10y + (-2 + -3y)

Reorder the terms:
-3 + 7y = -2 + 10y + -3y

Combine like terms: 10y + -3y = 7y
-3 + 7y = -2 + 7y

Add '-7y' to each side of the equation.
-3 + 7y + -7y = -2 + 7y + -7y

Combine like terms: 7y + -7y = 0
-3 + 0 = -2 + 7y + -7y
-3 = -2 + 7y + -7y

Combine like terms: 7y + -7y = 0
-3 = -2 + 0
-3 = -2

Solving
-3 = -2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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