2y+(y+-3)=4(y+-5)

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Solution for 2y+(y+-3)=4(y+-5) equation:



2y+(y+-3)=4(y+-5)
We move all terms to the left:
2y+(y+-3)-(4(y+-5))=0
We add all the numbers together, and all the variables
2y+(y-3)-(4(y-5))=0
We get rid of parentheses
2y+y-(4(y-5))-3=0
We calculate terms in parentheses: -(4(y-5)), so:
4(y-5)
We multiply parentheses
4y-20
Back to the equation:
-(4y-20)
We add all the numbers together, and all the variables
3y-(4y-20)-3=0
We get rid of parentheses
3y-4y+20-3=0
We add all the numbers together, and all the variables
-1y+17=0
We move all terms containing y to the left, all other terms to the right
-y=-17
y=-17/-1
y=+17

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