2y+(y+-3)=4(y+-5)

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Solution for 2y+(y+-3)=4(y+-5) equation: 



2y+(y+-3)=4(y+-5)

We move all terms to the left:

2y+(y+-3)-(4(y+-5))=0

We add all the numbers together, and all the variables

2y+(y-3)-(4(y-5))=0

We get rid of parentheses

2y+y-(4(y-5))-3=0



We calculate terms in parentheses: -(4(y-5)), so:

4(y-5)

We multiply parentheses

4y-20

Back to the equation:

-(4y-20)



We add all the numbers together, and all the variables

3y-(4y-20)-3=0

We get rid of parentheses

3y-4y+20-3=0

We add all the numbers together, and all the variables

-1y+17=0

We move all terms containing y to the left, all other terms to the right

-y=-17

y=-17/-1

y=+17

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