2y+(y-6)=7y-3(y-10)

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Solution for 2y+(y-6)=7y-3(y-10) equation: 



2y+(y-6)=7y-3(y-10)

We move all terms to the left:

2y+(y-6)-(7y-3(y-10))=0

We get rid of parentheses

2y+y-(7y-3(y-10))-6=0



We calculate terms in parentheses: -(7y-3(y-10)), so:

7y-3(y-10)

We multiply parentheses

7y-3y+30

We add all the numbers together, and all the variables

4y+30

Back to the equation:

-(4y+30)



We add all the numbers together, and all the variables

3y-(4y+30)-6=0

We get rid of parentheses

3y-4y-30-6=0

We add all the numbers together, and all the variables

-1y-36=0

We move all terms containing y to the left, all other terms to the right

-y=36

y=36/-1

y=-36

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