2y+10+3y=24-(-2y)

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Solution for 2y+10+3y=24-(-2y) equation: 



2y+10+3y=24-(-2y)

We move all terms to the left:

2y+10+3y-(24-(-2y))=0

We add all the numbers together, and all the variables

5y-(24-(-2y))+10=0



We calculate terms in parentheses: -(24-(-2y)), so:

24-(-2y)

determiningTheFunctionDomain
-(-2y)+24

We get rid of parentheses

2y+24

Back to the equation:

-(2y+24)



We get rid of parentheses

5y-2y-24+10=0

We add all the numbers together, and all the variables

3y-14=0

We move all terms containing y to the left, all other terms to the right

3y=14

y=14/3

y=4+2/3

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