2y+10+3y=24-(-2y)

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Solution for 2y+10+3y=24-(-2y) equation:



2y+10+3y=24-(-2y)
We move all terms to the left:
2y+10+3y-(24-(-2y))=0
We add all the numbers together, and all the variables
5y-(24-(-2y))+10=0
We calculate terms in parentheses: -(24-(-2y)), so:
24-(-2y)
determiningTheFunctionDomain -(-2y)+24
We get rid of parentheses
2y+24
Back to the equation:
-(2y+24)
We get rid of parentheses
5y-2y-24+10=0
We add all the numbers together, and all the variables
3y-14=0
We move all terms containing y to the left, all other terms to the right
3y=14
y=14/3
y=4+2/3

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