2y+100+(-12/7y)+90-10=180

Solution for 2y+100+(-12/7y)+90-10=180 equation:

2y+100+(-12/7y)+90-10=180

We move all terms to the left:

2y+100+(-12/7y)+90-10-(180)=0


Domain of the equation: 7y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

2y+(-12/7y)=0

We get rid of parentheses

2y-12/7y=0

We multiply all the terms by the denominator


2y*7y-12=0

Wy multiply elements

14y^2-12=0

a = 14; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·14·(-12)
Δ = 672
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{672}=\sqrt{16*42}=\sqrt{16}*\sqrt{42}=4\sqrt{42}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{42}}{2*14}=\frac{0-4\sqrt{42}}{28}
=-\frac{4\sqrt{42}}{28}
=-\frac{\sqrt{42}}{7}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{42}}{2*14}=\frac{0+4\sqrt{42}}{28}
=\frac{4\sqrt{42}}{28}
=\frac{\sqrt{42}}{7}
$