2y+12+4y-6=48

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Solution for 2y+12+4y-6=48 equation: 



2y+12+4y-6=48

We move all terms to the left:

2y+12+4y-6-(48)=0

We add all the numbers together, and all the variables

6y-42=0

We move all terms containing y to the left, all other terms to the right

6y=42

y=42/6

y=7

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