2y+12+4y=3(2y+5)-3

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Solution for 2y+12+4y=3(2y+5)-3 equation: 



2y+12+4y=3(2y+5)-3

We move all terms to the left:

2y+12+4y-(3(2y+5)-3)=0

We add all the numbers together, and all the variables

6y-(3(2y+5)-3)+12=0



We calculate terms in parentheses: -(3(2y+5)-3), so:

3(2y+5)-3

We multiply parentheses

6y+15-3

We add all the numbers together, and all the variables

6y+12

Back to the equation:

-(6y+12)



We get rid of parentheses

6y-6y-12+12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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