2y+12=-8(y+6)

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Solution for 2y+12=-8(y+6) equation:



2y+12=-8(y+6)
We move all terms to the left:
2y+12-(-8(y+6))=0
We calculate terms in parentheses: -(-8(y+6)), so:
-8(y+6)
We multiply parentheses
-8y-48
Back to the equation:
-(-8y-48)
We get rid of parentheses
2y+8y+48+12=0
We add all the numbers together, and all the variables
10y+60=0
We move all terms containing y to the left, all other terms to the right
10y=-60
y=-60/10
y=-6

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