2y+12=-8(y+6)

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Solution for 2y+12=-8(y+6) equation: 



2y+12=-8(y+6)

We move all terms to the left:

2y+12-(-8(y+6))=0



We calculate terms in parentheses: -(-8(y+6)), so:

-8(y+6)

We multiply parentheses

-8y-48

Back to the equation:

-(-8y-48)



We get rid of parentheses

2y+8y+48+12=0

We add all the numbers together, and all the variables

10y+60=0

We move all terms containing y to the left, all other terms to the right

10y=-60

y=-60/10

y=-6

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