2y+12=6(y-4)

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Solution for 2y+12=6(y-4) equation: 



2y+12=6(y-4)

We move all terms to the left:

2y+12-(6(y-4))=0



We calculate terms in parentheses: -(6(y-4)), so:

6(y-4)

We multiply parentheses

6y-24

Back to the equation:

-(6y-24)



We get rid of parentheses

2y-6y+24+12=0

We add all the numbers together, and all the variables

-4y+36=0

We move all terms containing y to the left, all other terms to the right

-4y=-36

y=-36/-4

y=+9

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