2y+1=(5y+3)/3

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Solution for 2y+1=(5y+3)/3 equation: 



2y+1=(5y+3)/3

We move all terms to the left:

2y+1-((5y+3)/3)=0

We multiply all the terms by the denominator


2y*3)-((5y+3)+1*3)=0

We add all the numbers together, and all the variables

2y*3)-((5y+3)=0

Wy multiply elements

6y^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{12}=0$

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