2y+1=3(y-1)-2

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Solution for 2y+1=3(y-1)-2 equation:



2y+1=3(y-1)-2
We move all terms to the left:
2y+1-(3(y-1)-2)=0
We calculate terms in parentheses: -(3(y-1)-2), so:
3(y-1)-2
We multiply parentheses
3y-3-2
We add all the numbers together, and all the variables
3y-5
Back to the equation:
-(3y-5)
We get rid of parentheses
2y-3y+5+1=0
We add all the numbers together, and all the variables
-1y+6=0
We move all terms containing y to the left, all other terms to the right
-y=-6
y=-6/-1
y=+6

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