2y+1=5(0.2y+1)-(4+y)

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Solution for 2y+1=5(0.2y+1)-(4+y) equation: 


Simplifying
2y + 1 = 5(0.2y + 1) + -1(4 + y)

Reorder the terms:
1 + 2y = 5(0.2y + 1) + -1(4 + y)

Reorder the terms:
1 + 2y = 5(1 + 0.2y) + -1(4 + y)
1 + 2y = (1 * 5 + 0.2y * 5) + -1(4 + y)
1 + 2y = (5 + 1y) + -1(4 + y)
1 + 2y = 5 + 1y + (4 * -1 + y * -1)
1 + 2y = 5 + 1y + (-4 + -1y)

Reorder the terms:
1 + 2y = 5 + -4 + 1y + -1y

Combine like terms: 5 + -4 = 1
1 + 2y = 1 + 1y + -1y

Combine like terms: 1y + -1y = 0
1 + 2y = 1 + 0
1 + 2y = 1

Add '-1' to each side of the equation.
1 + -1 + 2y = 1 + -1

Combine like terms: 1 + -1 = 0
0 + 2y = 1 + -1
2y = 1 + -1

Combine like terms: 1 + -1 = 0
2y = 0

Solving
2y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '2'.
y = 0

Simplifying
y = 0

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