2y+1=5(0.2y+1)-(4-y)

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Solution for 2y+1=5(0.2y+1)-(4-y) equation:


Simplifying
2y + 1 = 5(0.2y + 1) + -1(4 + -1y)

Reorder the terms:
1 + 2y = 5(0.2y + 1) + -1(4 + -1y)

Reorder the terms:
1 + 2y = 5(1 + 0.2y) + -1(4 + -1y)
1 + 2y = (1 * 5 + 0.2y * 5) + -1(4 + -1y)
1 + 2y = (5 + 1y) + -1(4 + -1y)
1 + 2y = 5 + 1y + (4 * -1 + -1y * -1)
1 + 2y = 5 + 1y + (-4 + 1y)

Reorder the terms:
1 + 2y = 5 + -4 + 1y + 1y

Combine like terms: 5 + -4 = 1
1 + 2y = 1 + 1y + 1y

Combine like terms: 1y + 1y = 2y
1 + 2y = 1 + 2y

Add '-1' to each side of the equation.
1 + -1 + 2y = 1 + -1 + 2y

Combine like terms: 1 + -1 = 0
0 + 2y = 1 + -1 + 2y
2y = 1 + -1 + 2y

Combine like terms: 1 + -1 = 0
2y = 0 + 2y
2y = 2y

Add '-2y' to each side of the equation.
2y + -2y = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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