2y+2(4-y)=8

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Solution for 2y+2(4-y)=8 equation: 



2y+2(4-y)=8

We move all terms to the left:

2y+2(4-y)-(8)=0

We add all the numbers together, and all the variables

2y+2(-1y+4)-8=0

We multiply parentheses

2y-2y+8-8=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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