2y+2(y+3)=34

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Solution for 2y+2(y+3)=34 equation:



2y+2(y+3)=34
We move all terms to the left:
2y+2(y+3)-(34)=0
We multiply parentheses
2y+2y+6-34=0
We add all the numbers together, and all the variables
4y-28=0
We move all terms containing y to the left, all other terms to the right
4y=28
y=28/4
y=7

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