2y+2(y-3)=-10

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Solution for 2y+2(y-3)=-10 equation: 



2y+2(y-3)=-10

We move all terms to the left:

2y+2(y-3)-(-10)=0

We add all the numbers together, and all the variables

2y+2(y-3)+10=0

We multiply parentheses

2y+2y-6+10=0

We add all the numbers together, and all the variables

4y+4=0

We move all terms containing y to the left, all other terms to the right

4y=-4

y=-4/4

y=-1

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